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3.4x^2+11.6x-11.6=0
a = 3.4; b = 11.6; c = -11.6;
Δ = b2-4ac
Δ = 11.62-4·3.4·(-11.6)
Δ = 292.32
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11.6)-\sqrt{292.32}}{2*3.4}=\frac{-11.6-\sqrt{292.32}}{6.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11.6)+\sqrt{292.32}}{2*3.4}=\frac{-11.6+\sqrt{292.32}}{6.8} $
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